ocesmon 62 muxtjy exarination calls for 100 kvp and 30 ma5 and made ata sid of 100 cm the exposu

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Adi S · Answer

Let us discuss the solution from the given question. Exposure mu at image receptor equal to t wh

Ina R · Answer

In first part, the SID is 100 cm and the SOD is at 80 centimeter. This is the height of the imag

Ankur S · Answer

this question we have given an object which is placed at the distance of 5 .0 centimeter to the

Abhishek Jana · Answer

Okay, so to solve for the exposure time of the pinhole camera, we need to follow the These steps

Madhur L · Answer

Hi, in this question we have this diagram of the cross section of a camera. This is having a sin

OCESMON 62 My examination calls for 100 kVp and 30 mA and made at a SID of 100 cm. The exposure at the image receptor is 0.85 mGy. If the same technique is used at a SID of 185 cm, what will be the new exposure? Round your answer to the nearest 0.01 mGy. Do not include units.