Question

(4) What is the molarity of a solution made by dissolving 5.25 g of potassium hydrogen phthalate in distilled water and making it up to 250 mL with distilled water in a volumetric flask? moles of solute molarity = liters of solution n = m / M = 5.25 / 204.23 = 0.026 / (250.00 x 10^-3) = 0.026 moles of KH(C8H4O4) = 0.104 mol/L (5) If 16.41 mL of aqueous NaOH is required to neutralise 20 mL of potas- sium hydrogen phthalate solution described in question 4 above, what is the molarity of the aqueous sodium hydroxide? Show your calculations as required below: (a) Write the reaction equation for the titration. NaOH + KH(C8H4O4) -> NaK(C8H4O4) + H2O (b) Calculate the number of moles of KHC8H4O4 used in the titration. n = m / M = 5.25 / 204.23 = 0.026 moles of KHC8H4O4 (c) Using the balance reaction equation, find the number of moles of NaOH that reacted. NaOH : KHC8H4O4 1 : 1 x = 0.026 moles of NaOH reacted (d) Calculate the molarity of the NaOH solution. MV = mV M(16.41 x 10^-3) = (0.104)(20 x 10^-3) .: M = 0.13 mol/L

          (4) What is the molarity of a solution made by dissolving 5.25 g of potassium
hydrogen phthalate in distilled water and making it up to 250 mL with
distilled water in a volumetric flask?
moles of solute
molarity = liters of solution
n = m / M
= 5.25 / 204.23
= 0.026 / (250.00 x 10^-3)
= 0.026 moles of KH(C8H4O4)
= 0.104 mol/L
(5) If 16.41 mL of aqueous NaOH is required to neutralise 20 mL of potas-
sium hydrogen phthalate solution described in question 4 above, what is
the molarity of the aqueous sodium hydroxide? Show your calculations
as required below:
(a) Write the reaction equation for the titration.
NaOH + KH(C8H4O4) -> NaK(C8H4O4) + H2O
(b) Calculate the number of moles of KHC8H4O4 used in the titration.
n = m / M
= 5.25 / 204.23
= 0.026 moles of KHC8H4O4
(c) Using the balance reaction equation, find the number of moles of NaOH that reacted.
NaOH : KHC8H4O4
1 : 1
x = 0.026 moles of NaOH reacted
(d) Calculate the molarity of the NaOH solution.
MV = mV
M(16.41 x 10^-3) = (0.104)(20 x 10^-3)
.: M = 0.13 mol/L

(4) What is the molarity of a solution made by dissolving 5.25 g of potassium
hydrogen phthalate in distilled water and making it up to 250 mL with
distilled water in a volumetric flask?
moles of solute
molarity = liters of solution
n = m / M
= 5.25 / 204.23
= 0.026 / (250.00 x 10^-3)
= 0.026 moles of KH(C8H4O4)
= 0.104 mol/L
(5) If 16.41 mL of aqueous NaOH is required to neutralise 20 mL of potas-
sium hydrogen phthalate solution described in question 4 above, what is
the molarity of the aqueous sodium hydroxide? Show your calculations
as required below:
(a) Write the reaction equation for the titration.
NaOH + KH(C8H4O4) -> NaK(C8H4O4) + H2O
(b) Calculate the number of moles of KHC8H4O4 used in the titration.
n = m / M
= 5.25 / 204.23
= 0.026 moles of KHC8H4O4
(c) Using the balance reaction equation, find the number of moles of NaOH that reacted.
NaOH : KHC8H4O4
1 : 1
x = 0.026 moles of NaOH reacted
(d) Calculate the molarity of the NaOH solution.
MV = mV
M(16.41 x 10^-3) = (0.104)(20 x 10^-3)
.: M = 0.13 mol/L

Added by Dana G.

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