00:09
Here, this is the rod, the central line, that's plus l over 2, and that's minus l over 2.
00:24
At a distance of y and negative y, choose two points which will have, it will make angle theta.
00:41
So the sum of the electric field will be given by this.
00:55
Let's call this de let's call this d epsilon and this to be theta so we have de equals to d epsilon cosine cosine now we have so charge here is d q and d q is given by lambda dy and on a separate diagram, lambda varies like this and over here at l over 2, the lambda values is al over 2.
02:21
So dq equals lambda d -y, which is a -y -d -y -d -y.
02:35
Now, total charge we can just integrate on the half of it and just match it to it, which so that comes out to be 2a times half y square or s squared over 4 so that is a l square over 4 so we find that a equals 4 q over l square now we go back to this equation we have d e equals 2 times g -evsson is 1 over 4 pi epsilon not times delta q over let's call this point to be x, x squared plus y square.
03:52
And then there is this cosine theta part.
03:55
Cosine theta will be given by y over that...