00:01
Dear students, which alkyne on ozonalysis will in the presence of dimethyl sulfide will give this compound.
00:08
This is our question.
00:11
Now here let us see on ozonlysis what will happen, this bond will break.
00:17
Out of these four alkyne options are there.
00:20
So here o and here o will be attached.
00:24
Therefore it must be cs3 c double bond o.
00:27
So, cs3 c double bond o.
00:30
Then after that, on opening it will have become cs3 c double bond o, then three carbon atoms, 1, 2, 1, 2, 3, c .ho.
00:49
This is cs3.
00:52
Now this one on ozurulysis, reductive ozonlysis, it will give like this.
00:59
So we'll have hydrogen here, then here double bond o, then here, 1, 2 ,000, and then here, 3rd carbon 1 2 3 1 2 3 then here then we'll have so on opening 1 2 3 4 5 6 this compound will form now on opening this one we'll get this will form this methyl is this one this will form this will and on opening this it has 1 2 3 4 5 6 7 carbon atoms but here 1.
01:50
1, 2, 3, 4, 5, 6, 7 carbon atoms.
01:52
Here also 7 carbon atoms.
01:54
So on opening this, we'll get the compound like this.
02:02
2, 3, 4, 5, 6, 7...