00:01
Hello students, according to the question we are going to find out the couple vector.
00:05
As per that, first we are going to find out x component of couple as per that mx is equals to 25 sin 40 degree into 0 .75.
00:31
From this we get mx is equals to 12 .05 newton meter.
00:38
Next we are going to find out the y component of couple.
00:51
From this we get my is equals to 25 cos 40 degree into 0 .75.
01:03
From this we get 6 .363 newton meter.
01:12
Next we are going to find out z component of couple as per that mz is equals to minus 25 cos 40 into 0 .3 minus 25 sin 40 into 0 .4 plus 25 sin 40 into 0 .4.
01:56
Now we will be getting the value mz is equals to 0 newton meter.
02:05
Now we are going to find out the couple vector.
02:17
As per that we can write m vector is equals to mx i cap plus myj cap plus mz k cap.
02:30
As per this we can write m vector is equals to 12 .052 i cap plus 6 .363 j cap.
02:49
Now next we are going to see the part b.
02:56
In part b, first we are going to take moment about x axis by force.
03:03
So moment mx is equals to f sin theta into 0 .75...