Question

1. Suppose 0.220 grams K2C2O4 required 36.48 mL of KMnO4 solution to reach the endpoint. What would be the concentration of the permanganate solution? 2. Solutions of containing the ferrous ion, Fe2+, are sometimes titrated with KMnO4. In this case, the ferrous ion is oxidized to the ferric ion, Fe2+ -> Fe3+ + e-. Write a balanced chemical equation for the reaction between MnO4- and Fe2+. 3. Calculate the mass percent of oxalate ion in H2C2O4·2H2O and (NH4)2C2O4·H2O. C2O4-2 mass=88 SO H2C2O4 x H2O / total mass x 100 = 88 / 126 x 100 = 69.84% (NH4)2 C2O4 x H2O / Total mass = 88 / 142 x 100 = 61.97%

          1. Suppose 0.220 grams K2C2O4 required 36.48 mL of KMnO4 solution to reach the endpoint. What would be the concentration of the permanganate solution?

2. Solutions of containing the ferrous ion, Fe2+, are sometimes titrated with KMnO4. In this case, the ferrous ion is oxidized to the ferric ion, Fe2+ -> Fe3+ + e-. Write a balanced chemical equation for the reaction between MnO4- and Fe2+.

3. Calculate the mass percent of oxalate ion in H2C2O4·2H2O and (NH4)2C2O4·H2O.
C2O4-2 mass=88 SO
H2C2O4 x H2O / total mass x 100 = 88 / 126 x 100 = 69.84%
(NH4)2 C2O4 x H2O / Total mass = 88 / 142 x 100 = 61.97%

1. Suppose 0.220 grams K2C2O4 required 36.48 mL of KMnO4 solution to reach the endpoint. What would be the concentration of the permanganate solution?

2. Solutions of containing the ferrous ion, Fe2+, are sometimes titrated with KMnO4. In this case, the ferrous ion is oxidized to the ferric ion, Fe2+ -> Fe3+ + e-. Write a balanced chemical equation for the reaction between MnO4- and Fe2+.

3. Calculate the mass percent of oxalate ion in H2C2O4·2H2O and (NH4)2C2O4·H2O.
C2O4-2 mass=88 SO
H2C2O4 x H2O / total mass x 100 = 88 / 126 x 100 = 69.84%
(NH4)2 C2O4 x H2O / Total mass = 88 / 142 x 100 = 61.97%

Added by Richard S.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Adi S

09/05/2023

Step 1

We can do this using the given mass and the molar mass of KC2O4. Moles of KC2O4 = (0.220 g) / (138.21 g/mol) = 0.00159 mol Now, we need to find the moles of KMnO4. The balanced chemical equation for the reaction between KMnO4 and KC2O4 is: 2 KMnO4 + 5 KC2O4 → 2 Show more…

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