On a rough horizontal surface, a body of mass 2 kg is given a velocity of 10 m/s. If the coefficient of friction is 0.2 and , the body will stop after covering a distance of (a) 10 m (b) 25 m (c) 50 m (d) 250 m
Added by Yash G.
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Step 1: Write the expression for distance covered by the body: \(d = \frac{\mu^2}{2} \times \frac{v^2}{2 \times g}\) Show more…
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Kamlesh G.
A block of mass $2 \mathrm{~kg}$ rests on a horizontal surface. A gradually increasing force is applied horizontally on the body by a light inextensible string tied to the body. If the body just begins to slide at $5 \mathrm{~N}$, the coefficient of static friction is $\left(g=10 \mathrm{~m} \mathrm{~s}^{-2}\right)$ (a) $0.025$ (b) $0.25$ (c) $0.01$ (d) $0.4$
A block slides with velocity of $10 \mathrm{~m} / \mathrm{s}$ on a rough horizontal surface. It comes to rest after covering a distance of $50 \mathrm{~m}$. If $g$ is $10 \mathrm{~m} / \mathrm{s}^{2}$, then the coefficient of dynamic friction between the block and the surface is a. $0.1$ b. 1 c. 10 d. 5
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