00:01
Hi, here in this given problem, linear mass density of the high e string that is given as mu high e is equal to 3 .09 into 10 dash to bar minus 4 kilogram per meter and that of low e string this is given as mu low e and that is equal to 5 .78 into 10 dash per minus 3 kilogram per meter now in the first part of the problem for the high e string tension created in it that is given as 56 point 4 -0 newton.
01:26
So speed of the wave produced in it, transverse wave produced in it, that will be given by v in the high e string is equal to the expression used is t, high, e, divided by mu, high, e and then plugging in all the known values this is 56 .40 newton divided by 3 .09 into 10 dash the power minus 4 and finally this is speed of the wave velocity of the wave created in the high e string comes out to be equal to 427 .2 meter per second which is the answer for the first part of the problem here.
02:28
Now in the second part of the problem, using the expression for this speed, speed of the wave created in a stretched string, v is equal to square root of t by mu, where mu is the linear mass density.
02:47
For v to be constant to keep the speed of the wave, same.
02:57
It is clear that tension created in the string that should be proportional to its linear mass density.
03:04
So, tension in low e string would be larger as its linear mass density is larger...