Question

On a winter day, a certain house loses \( 3.15 \times 10^{8} \mathrm{~J} \) of heat to the outside. What is the total change in entropy due to this heat transfer alone, assuming an average indoor temperature of \( 21.5^{\circ} \mathrm{C} \) and an average outdoor temperature of \( 4.91^{\circ} \mathrm{C} \) ? Select the correct answer \( 7.04 \times 10^{4} \mathrm{~J} / \mathrm{K} \) \( 6.39 \times 10^{4} \mathrm{~J} / \mathrm{K} \) \( 8.11 \times 10^{4} \mathrm{~J} / \mathrm{K} \) \( 2.28 \times 10^{4} \mathrm{~J} / \mathrm{K} \) \( 9.98 \times 10^{4} \mathrm{~J} / \mathrm{K} \)

          On a winter day, a certain house loses \( 3.15 \times 10^{8} \mathrm{~J} \) of heat to the outside. What is the total change in entropy due to this heat transfer alone, assuming an average indoor temperature of \( 21.5^{\circ} \mathrm{C} \) and an average outdoor temperature of \( 4.91^{\circ} \mathrm{C} \) ?

Select the correct answer
\( 7.04 \times 10^{4} \mathrm{~J} / \mathrm{K} \)
\( 6.39 \times 10^{4} \mathrm{~J} / \mathrm{K} \)
\( 8.11 \times 10^{4} \mathrm{~J} / \mathrm{K} \)
\( 2.28 \times 10^{4} \mathrm{~J} / \mathrm{K} \)
\( 9.98 \times 10^{4} \mathrm{~J} / \mathrm{K} \)

On a winter day, a certain house loses 3.15 × 10^8 J of heat to the outside. What is the total change in entropy due to this heat transfer alone, assuming an average indoor temperature of 21.5^∘C and an average outdoor temperature of 4.91^∘C ?

Select the correct answer
7.04 × 10^4 J / K
6.39 × 10^4 J / K
8.11 × 10^4 J / K
2.28 × 10^4 J / K
9.98 × 10^4 J / K

Added by Niyousha

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