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Hey there, welcome to numerary.
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So we have a professor who's provided an exam to his or her class of 40 students and the scores are reported below in this data table.
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So we would have to find several statistics based on these scores including a mean median and standard deviation.
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So let's first find a mean first.
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So mean will be denoted as x bar equals the sum of all the values divide by the total number of students.
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Total number of students in this case would be 40.
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So we're going to solve this in our calculator, and you should get a mean of around 60 .52.
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Around it is going 60 .53.
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So this will be our mean.
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And then let's go to the next one.
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Part two.
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Let's actually make it closer here.
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Okay.
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Part two.
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So for part two, it asks for the median, right? so the median is basically the middle value of the data set.
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So we're going to look at what is the middle value here.
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So let's see what we have here.
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So we're going to start from the edges.
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And the median is going to be between two values.
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It's going to be between 59 and 60.
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Therefore, we're going to add them both together and find an average.
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In order to get the middle value, the median, okay? 59 plus 60, and the vibaba 2 equals 59 .5.
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Okay, so this will be our median here.
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Let's signify it.
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Median equals.
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And then part three.
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So let's try part three here.
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So if we're part three, we're going to find the standard deviation here.
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So let's find that.
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Part three, standard deviation, we denote it as...