00:01
Hello everyone, let us look into the equation.
00:04
Let t represents the time we are measuring in minutes between two calls.
00:15
Therefore, we can have lambda equal to 10 calls per hour which means that 1 by 6 call per minute.
00:27
Hence, the lambda value is 1 by 6.
00:30
Then the random variable t is approximated to exponential of lambda equal to 1 by 6.
00:36
Then from this we can have p of t greater than 5 which is equal to exponential of minus 5 by 6 which is equal to 0 .434598.
00:53
And the next one is we can say that the time between calls, between two calls follow exponential distribution.
01:10
Therefore, we can have the call rate is equal to lambda which is equal to 1 by 6 call per minute.
01:21
So, here x represents the number of calls within t minutes.
01:32
Therefore, take t equal to 5...