On the floor of an elevator, a block of mass 50 kg is placed on which another block of mass 20 kg is also placed. The elevator is moving up with a constant acceleration 1.5 m/s^2 . Force exerted by 20 kg block on the 50 kg block is nearly.
Added by Christian N.
Step 1
First, we need to find the net force acting on the 20 kg block. Since the elevator is moving up with an acceleration of 1.5 m/s^2, the net force acting on the 20 kg block is given by Newton's second law: F_net = m * a, where m is the mass of the block and a is the Show more…
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A 2010 -kg elevator moves with an upward acceleration of $1.50 \mathrm{m} / \mathrm{s}^{2} .$ What is the force exerted by the cable on the elevator?
(a) An elevator of mass m moving upward has two forces acting on it: the upward force of tension in the cable and the downward force due to gravity. When the elevator is accelerating upward, which is greater, T or w? (b) When the elevator is moving at a constant velocity upward, which is greater, T or w? (c) When the elevator is moving upward, but the acceleration is downward, which is greater, T or w? (d) Let the elevator have a mass of 1 500 kg and an upward acceleration of 2.5 $\mathrm{m} / \mathrm{s}^{2} .$ Find $T .$ Is your answer consistent with the answer to part (a)? (e) The elevator of part (d) now moves with a constant upward velocity of 10 m/s. Find T. Is your answer consistent with your answer to part (b)? (f) Having initially moved upward with a constant velocity, the elevator begins to accelerate downward at 1.50 $\mathrm{m} / \mathrm{s}^{2}$ . Find $T$ . Is your answer consistent with your answer to part ( $(\mathrm{c})$ ?
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