00:01
Hello guys in this problem we have a level horizontal surface.
00:06
We have two bullet, bullet one and bullet two.
00:12
The initial height of both bullet above the ground are equal.
00:17
Let's suppose the initial height is h.
00:19
The bullet 1 is dropped towards the ground and the bullet 2 is given our initial horizontal velocity 1 ,000 feet per second.
00:34
For both bullet, the acceleration is uniform, that is g, in the vertical downward direction.
00:42
We have to find out which bullet falls on the ground force.
00:46
For this, let's assume in upward direction as y direction.
00:50
For the first one, we can write the displacement delta y equals the initial velocity of the first one in vertical direction into the time of travel t minus half times acceleration due to gravity times t squared.
01:10
Since the first one is dropped from rest, hence the initial velocity in vertical direction will be zero...