One component of a magnetic field has a magnitude of 0.0433 T and points along the +x axis, while the other component has a magnitude of 0.0717 T and points along the -y axis. A particle carrying a charge of $+1.60 imes 10^{-5}$ C is moving along the +z axis at a speed of $4.20 imes 10^3$ m/s. (a) Find the magnitude of the net magnetic force that acts on the particle. (b) Determine the angle that the net force makes with respect to the +x axis.
Added by William T.
Close
Step 1
Given: q = 1.60 x 10^-5 C v = 4.20 x 10^3 m/s in the +z direction B = 0.0433i - 0.0717j T Calculate the magnetic force vector: F = (1.60 x 10^-5 C)(4.20 x 10^3 m/s)(0.0433i - 0.0717j) F = 6.72 x 10^-2 (0.0433i - 0.0717j) F = 0.00291i - 0.00482j N Show more…
Show all steps
Your feedback will help us improve your experience
Prabhu Ramji and 61 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
One component of a magnetic field has a magnitude of $0.048 \mathrm{T}$ and points along the $+x$ axis, while the other component has a magnitude of $0.065 \mathrm{T}$ and points along the $-y$ axis. A particle carrying a charge of $+2.0 \times 10^{-5} \mathrm{C}$ is moving along the $+z$ axis at a speed of $4.2 \times \mathrm{x}$ $10^{3} \mathrm{m} / \mathrm{s}$ (a) Find the magnitude of the net magnetic force that acts on the particle. (b) Determine the angle that the net force makes with respect to the $+x$ axis.
Adi S.
A particle with charge 7.80$\mu \mathrm{C}$ is moving with velocity $\vec{v}=-\left(3.80 \times 10^{3} \mathrm{m} / \mathrm{s}\right) \hat{\jmath} .$ The magnetic force on the particle is measured to be $\overrightarrow{\boldsymbol{F}}=+\left(7.60 \times 10^{-3} \mathrm{N}\right) \hat{\boldsymbol{i}} \left(5.20 \times 10^{-3} \mathrm{N}\right) \hat{\boldsymbol{k}}$ (a) Calculate all the components of the magnetic field you can from this information. (b) Are there components of the magnetic field that are not determined by the measurement of the force? Explain. (c) Calculate the scalar product $\overrightarrow{\boldsymbol{B}} \cdot \overrightarrow{\boldsymbol{F}}$ What is the angle between $\overrightarrow{\boldsymbol{B}}$ and $\overrightarrow{\boldsymbol{F}} ?$
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD