one cubic metre of aluminium has a mass of 2,70×10³ kg and 1.00m³ of iron has a mass of 7,86×10⁷ kg. what is the radius of the solid aluminium sphere that will balance a solid iron sphere of radius 2,00cm on an equal arm balance
Added by Bongeka K.
Step 1
The formula for the volume of a sphere is V = 4/3πr³. So, the volume of the iron sphere is V = 4/3π(2cm)³ = 33.51 cm³. We need to convert this volume to m³ because the given mass of iron is in kg/m³. 1 m³ = 1,000,000 cm³, so 33.51 cm³ = 33.51 x 10^-6 Show more…
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One cubic meter (1.00 m3) of aluminum has a mass of 2.70 × 103 kg, and 1.00 m3 of iron has a mass of 7.86 × 103 kg. Find the radius of a solid aluminum sphere that will balance a solid iron sphere of radius 2.00 cm on an equal-arm balance
Paul G.
One cubic meter $\left(1.00 \mathrm{m}^{3}\right)$ of aluminum has a mass of $2.70 \times 10^{3} \mathrm{kg},$ and the same volume of iron has a mass of $7.86 \times 10^{3} \mathrm{kg} .$ Find the radius of a solid aluminum sphere that will balance a solid iron sphere of radius $2.00 \mathrm{cm}$ on an equal-arm balance.
One cubic meter $\left(1.00 \mathrm{~m}^{3}\right)$ of aluminum has a mass of $2.70 \times 10^{3} \mathrm{~kg}$, and $1.00 \mathrm{~m}^{3}$ of iron has a mass of $7.86 \times 10^{3} \mathrm{~kg} .$ Find the radius of a solid aluminum sphere that balances a solid iron sphere of radius $2.00$ $\mathrm{cm}$ on an equal-arm balance.
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