Given:
Pressure, P = 200 kPa = 200,000 Pa
Initial volume, V1 = 0.835 m³
Final volume, V2 = 0.841 m³
Work done, W = P * (V2 - V1)
W = 200,000 Pa * (0.841 m³ - 0.835 m³)
W = 200,000 Pa * 0.006 m³
W = 1,200 J
Therefore, the work done by the water on the piston is
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