00:01
Hi, here in this given problem there are two light bulbs and for these two light bulbs, power is 25 watt for the dim bulb and it is used at 120 volt and for the second one, 100 watt and 120 volt.
00:34
Now in the first part of the problem we have to find the resistance of the two bulbs.
00:42
Using an expression for the power p is equal to v square by r so r will be given by v square by p so r 1 that is v square means square of 120 divided by power p 1 which is 25 watt so this r 1 is calculated to be equal to 576 om similarly r 2 resistance of the element of second bulb square of 120 divided by 100.
01:23
So r2 is calculated to be equal to 144 om.
01:30
Means these two are the answers for the first part of this given problem here.
01:40
Then in the second part of the problem we have to find the time taken by one column of charge to pass through the dim bulb.
01:51
So for the dim bulb, means the bulb having 25 watt power.
02:02
Using another expression for the power, p is equal to v multiplied by i, we get an expression for current i as p by v, and another expression for the current, that is the time rate of flow of charge also.
02:18
So, the time to pass 1 amp or, sorry, 1 coulum of charge will be given by t is equal to q multiplied by v by p.
02:30
This is 1 .00 column multiplied by 120 volt divided by power 25 watt...