Question

One of the widely used correlations to describe the variation of the viscosity of gases is the power-law equation given by $\mu/\mu_0 = (T/T_0)^n$, where $\mu_0$ and $T_0$ are the reference viscosity and temperature, respectively. Calculate the air viscosity at 500 Celsius using the power-law equation. Take the reference temperature as 0 Celsius and n = 0.666 for the atmospheric air.

          One of the widely used correlations to describe the variation of the viscosity of gases is the power-law equation given by $\mu/\mu_0 = (T/T_0)^n$, where $\mu_0$ and $T_0$ are the reference viscosity and temperature, respectively. Calculate the air viscosity at 500 Celsius using the power-law equation. Take the reference temperature as 0 Celsius and n = 0.666 for the atmospheric air.
        
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One of the widely used correlations to describe the variation of the viscosity of gases is the power-law equation given by μ/μ0 = (T/T0)^n, where μ0 and T0 are the reference viscosity and temperature, respectively. Calculate the air viscosity at 500 Celsius using the power-law equation. Take the reference temperature as 0 Celsius and n = 0.666 for the atmospheric air.

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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One of the widely used correlations to describe the variation of the viscosity of gases is the power-law equation given by μ/μo = (T/To)^n, where μo and To are the reference viscosity and temperature, respectively. Calculate the air viscosity at 500 Celsius using the power-law equation. Take the reference temperature as 0 Celsius and n = 0.666 for the atmospheric air.
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The variation with temperature of the viscosity of air is represented well by the empirical Sutherland correlation \[\mu=\frac{b T^{1 / 2}}{1+S / T}\] Best-fit values of $b$ and $S$ are given in Appendix A. Develop an equation in SI units for kinematic viscosity versus temperature for air at atmospheric pressure. Assume ideal gas behavior. Check by using the equation to compute the kinematic viscosity of air at $0^{\circ} \mathrm{C}$ and at $100^{\circ} \mathrm{C}$ and comparing to the data in Appendix 10 (Table $A .10$ ); plot the kinematic viscosity for a temperature range of $0^{\circ} \mathrm{C}$ to $100^{\circ} \mathrm{C}$, using the equation and the data in Table A.10.

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The variation with temperature of the viscosity of air is represented well by the empirical Sutherland correlation \[\mu=\frac{b T^{1 / 2}}{1+S / T}\] Best-fit values of $b$ and $S$ are given in Appendix A. Develop an equation in SI units for kinematic viscosity versus temperature for air at atmospheric pressure. Assume ideal gas behavior. Check by using the equation to compute the kinematic viscosity of air at $0^{\circ} \mathrm{C}$ and at $100^{\circ} \mathrm{C}$ and comparing to the data in Appendix 10 (Table $A .10$ ); plot the kinematic viscosity for a temperature range of $0^{\circ} \mathrm{C}$ to $100^{\circ} \mathrm{C}$, using the equation and the data in Table A.10.

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Transcript

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00:01 For this problem, we are told that the dynamic viscosity mu is given by this relation bt to the power half all over 1 plus s over t.
00:12 And this is a sutherland equation.
00:15 Now, we are told to find new, which is mu over row.
00:24 From equation of state for a perfect gas, p is equal to row rt.
00:36 So you can say that row is p over r t i can see therefore that new which is equal to mu over row is equal to mu over times r t and this will be r t over p times this will be r t over p this entire relationship for the subtle and equation p t to the power half all over one plus s over t i can bring t here and so i'll have that new is equal to r b over p times t to the power 3 over 2 all over 1 plus s over t...
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