Question

One sample T hypothesis test: \( \mu \) : Mean of variable \[ \begin{array}{l} \mathrm{H}_{0}: \mu=98 \\ \mathrm{H}_{\mathrm{A}}: \mu \neq 98 \end{array} \] Hypothesis test results: \begin{tabular}{|c|c|c|c|c|c|} \hline Variable - & Sample Mean \( \hat{\sim} \) & & & & \\ \hline BODY TEMP & 98.44 & 0.2550907 & 29 & 1.7248767 & 0.0952 \\ \hline HEART RATE & 76 & 1.131574 & 29 & -19.441945 & \( <0.0001 \) \\ \hline \end{tabular}

          One sample T hypothesis test:
\( \mu \) : Mean of variable
\[
\begin{array}{l}
\mathrm{H}_{0}: \mu=98 \\
\mathrm{H}_{\mathrm{A}}: \mu \neq 98
\end{array}
\]

Hypothesis test results:
\begin{tabular}{|c|c|c|c|c|c|}
\hline Variable - & Sample Mean \( \hat{\sim} \) & & & & \\
\hline BODY TEMP & 98.44 & 0.2550907 & 29 & 1.7248767 & 0.0952 \\
\hline HEART RATE & 76 & 1.131574 & 29 & -19.441945 & \( <0.0001 \) \\
\hline
\end{tabular}

One sample T hypothesis test:
μ : Mean of variable

H0: μ=98
HA: μ≠ 98

Hypothesis test results:

Variable - Sample Mean ∼̂

BODY TEMP 98.44 0.2550907 29 1.7248767 0.0952

HEART RATE 76 1.131574 29 -19.441945 <0.0001

Added by Alicia S.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Rosina Dapaah

Step 1

- The alternative hypothesis (\(H_A\)) suggests that the mean (\(\mu\)) of the variable is not equal to 98. This is a two-tailed test because we are looking for differences in both directions (higher or lower than 98). Show more…

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One sample T hypothesis test: \( \mu \) : Mean of variable \[ \begin{array}{l} \mathrm{H}_{0}: \mu=98 \\ \mathrm{H}_{\mathrm{A}}: \mu \neq 98 \end{array} \] Hypothesis test results: \begin{tabular}{|c|c|c|c|c|c|} \hline Variable - & Sample Mean \( \hat{\sim} \) & & & & \\ \hline BODY TEMP & 98.44 & 0.2550907 & 29 & 1.7248767 & 0.0952 \\ \hline HEART RATE & 76 & 1.131574 & 29 & -19.441945 & \( <0.0001 \) \\ \hline \end{tabular}