Question

One-Sample Test Test Value = 80 95% Confidence Interval of the Difference Mean Difference df Sig. (2-tailed) Degree (t) -0.864 15 0.401 -2.81250 Lower -9.7499 Upper 4.1249 Statistical Model About Population mean Assumptions 1- Population is normal 2- Variance is unknown 3- SRS 4- n = 16–30 H0: ? = 80 H1: ? ? 80 Test Name One Sample T-test Output P-value = 0.401 Decision Since P-value = 0.401 > ? = 0.05, we accept H0 and decide that the average degree is equal to 80 ? = 0.05

          One-Sample Test
Test Value = 80
95% Confidence Interval of the Difference
Mean Difference
df   Sig. (2-tailed)
Degree (t) -0.864   15   0.401   -2.81250
Lower   -9.7499   Upper   4.1249
Statistical Model
About Population mean
Assumptions
1- Population is normal
2- Variance is unknown
3- SRS
4- n = 16–30
H0: ? = 80
H1: ? ? 80
Test Name
One Sample T-test
Output
P-value = 0.401
Decision
Since P-value = 0.401 > ? = 0.05, we accept H0 and decide that the average degree is equal to 80
? = 0.05

Show more…

One-Sample Test
Test Value = 80
95% Confidence Interval of the Difference
Mean Difference
df Sig. (2-tailed)
Degree (t) -0.864 15 0.401 -2.81250
Lower -9.7499 Upper 4.1249
Statistical Model
About Population mean
Assumptions
1- Population is normal
2- Variance is unknown
3- SRS
4- n = 16–30
H0: ? = 80
H1: ? ? 80
Test Name
One Sample T-test
Output
P-value = 0.401
Decision
Since P-value = 0.401 > ? = 0.05, we accept H0 and decide that the average degree is equal to 80
? = 0.05

Added by Ryan R.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Adi S

05/09/2023

Step 1

Given information: - Test value: 9593 - Confidence interval of the difference: Lower = 7499, Upper = 13499 - Sample mean: unknown (let's call it $\bar{x}$) - Population mean: unknown (let's call it $\mu$) - Population variance: unknown - Sample size: unknown Show more…

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One-Sample Test Test Value = 80 95% Confidence Interval of the Difference Lower Upper -9.7499 4.1249 Mean Difference -2.81250 df 15 Sig. (2-tailed) 0.401 Sample T-test Statistical Model About Population mean Assumptions 1- Population is normal 2- Variance is unknown 3- SRS 4- n = 16–30 H0: μ = 80 H1: μ ≠ 80 Test Name One Sample T-test Output P-value = 0.401 Decision Since P-value = 0.401 > α = 0.05, we accept H0 and decide that the average degree is equal to 80 α = 0.05

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