32. Construct a series voltage divider circuit whose total resistance is 2400 ? as illustrated in Figure 2.32. (a) Suppose $V_1 = 0.75V_s$ and $V_2 = 0.25V_s$ Find the values of $R_1$, $R_2$, and $R_3$ (b) Suppose $V_1 = 0.8V_s$ and $V_2 = 0.5V_s$ Find the values of $R_1$, $R_2$, and $R_3$ (c) Suppose $V_1 = 0.8V_s$ and $V_2 = 0.5V_s$ Find the values of $R_1$, $R_2$, and $R_3$ ANSWER: (c) $R_1 = R_2 = 960 \Omega$, $R_3 = 480 \Omega$
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In a series voltage divider circuit, the total resistance is the sum of the individual resistances. In this case, the total resistance is given as 2400Ω. Using Ohm's Law, we can calculate the current flowing through the circuit: I = V / R Where I is the Show more…
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Assume the resistance values are $R_{1}=2400 \Omega, R_{2}=1400 \Omega, R_{3}=4500 \Omega,$ and $R_{4}=6000 \Omega,$ and the battery emfs are $\varepsilon_{1}=1.5 \mathrm{V}$ and $\varepsilon_{2}=3.0 \mathrm{V},$ unless stated otherwise. Use the approach from Problems 50 and 51 to analyze the circuit in Figure P19.52. What is the current through the battery and resistor $R_{1}$ ? Hint: First redraw the circuit so that the parallel and series resistor combinations are more obvious.
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DC Circuits: Batteries, Resistors, and Kirchhoff’s Rules
Assume the resistance values are $R_{1}=2400 \Omega, R_{2}=1400 \Omega, R_{3}=4500 \Omega,$ and $R_{4}=6000 \Omega,$ and the battery emfs are $\varepsilon_{1}=1.5 \mathrm{V}$ and $\varepsilon_{2}=3.0 \mathrm{V},$ unless stated otherwise. Analyze the circuit in Figure P19.48. a. Express the resistors in parallel as a single equivalent resistor. What is the value of this resistor? b. Combine this equivalent resistor with $R_{1}$ to get the total equivalent resistance of the circuit. What is the value of this resistor? c. The circuit is now "reduced" to a battery in series with a single equivalent resistance. Use your result from part (b) to find the current through the battery and resistor $R_{1}$.
Assume the resistance values are $R_{1}=2400 \Omega, R_{2}=1400 \Omega, R_{3}=4500 \Omega,$ and $R_{4}=6000 \Omega,$ and the battery emfs are $\varepsilon_{1}=1.5 \mathrm{V}$ and $\varepsilon_{2}=3.0 \mathrm{V},$ unless stated otherwise. Use your results from Problem 50 to find the current through $R_{2}$ in Figure P19.48. Hint: First find the voltage across the parallel combination of resistors.
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