Question

\( \operatorname{Lim}_{x \rightarrow 3} \frac{x^{3}-27}{x-3} \) (hint simplify to avoid dividing by zero and \( \left(\mathrm{a}^{3}-\mathrm{b}^{3}\right)=(\mathrm{a}-\mathrm{b})\left(\mathrm{a}^{2}+\mathrm{ab}+\mathrm{b}^{2}\right) \) 81 27 \( -27 \) \( -81 \)

          \( \operatorname{Lim}_{x \rightarrow 3} \frac{x^{3}-27}{x-3} \)
(hint simplify to avoid dividing by zero and \( \left(\mathrm{a}^{3}-\mathrm{b}^{3}\right)=(\mathrm{a}-\mathrm{b})\left(\mathrm{a}^{2}+\mathrm{ab}+\mathrm{b}^{2}\right) \)
81
27
\( -27 \)
\( -81 \)

Limx → 3(x^3-27)/(x-3)
(hint simplify to avoid dividing by zero and (a^3-b^3)=(a-b)(a^2+ab+b^2)
81
27
-27
-81

Added by Jose Angel V.

Calculus for AP

Jon Rogawski & Colin Adams 3rd Edition

Chapter 2

Instant Answer

Solved by Expert Steven Clarke

Step 1

Step 1: Recognize that the given limit is: \[ \lim_{x \rightarrow 3} \frac{x^3 - 27}{x - 3} \] Show more…

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\( \operatorname{Lim}_{x \rightarrow 3} \frac{x^{3}-27}{x-3} \) (hint simplify to avoid dividing by zero and \( \left(\mathrm{a}^{3}-\mathrm{b}^{3}\right)=(\mathrm{a}-\mathrm{b})\left(\mathrm{a}^{2}+\mathrm{ab}+\mathrm{b}^{2}\right) \) 81 27 \( -27 \) \( -81 \)