00:01
Hi there, so for this problem, we're told that oppositely charged parallel plates are separated, a distance to word we're going to call the distance d, and that is equal to 5 .62 millimeters.
00:15
That is the same as 5 .62 times 10 to the minus 3 meters, because remember that melee means 10 to the minus 3.
00:24
A potential difference of 600 volts it sits between the plates.
00:30
So the potential difference between the plates, it 600 volts.
00:35
Now, with that said, for part a of this problem, we are as the magnetited of the electric field between the plates.
00:43
And for that, we use the fact that the electric field is equal to the potential difference divided by the separation distance between the plates.
00:50
So that will be 600 balls divided by the separation distance.
00:54
That is 5 .62 times 10 to the minus 3 meters.
00:59
So using our calculator, we obtain a value of 1 .068 times 10 to the phi in units of neutons per column.
01:20
So that's a solution for par a of this problem.
01:25
Now for part b, we are asked about what is the mandatory? of the force on an electron between the plates.
01:34
Now for this, we use the fact that the electric field is equal to the charge of an electron, in this case, times the electric field.
01:43
So if we want the electric force, that will be just simply the charge of an electron, that is 1 .6 times 10 to the minus 19 columns.
01:52
This times the electric field that we determined from before, that is 1 .068 times 10 to the 5 .5.
02:01
Newtons per column.
02:04
So by doing this product in here we obtain a value of 1 .71 times 10 to the minus 14 newtons...