0:00
Hello everyone.
00:01
So for the given question we have a number of carbocotines.
00:04
So there are five carbocotines given in the question we need to find which of the following will be the most table and basically we have to arrange these carbocotines in the increasing order of the stability from the least table to the most stable and explain what is the reason for this stability so first of all we will mark these carbocytes so this is the first carbon å.
00:26
This is 2nd, this is third, then fourth, and then 5th carbocotign.
00:32
Now if we talk about this stability.
00:34
So in the first carbon, what we have is this is the carbohydrate and this is the carbon atom and if you talk about the number of alpha hydrogen, that is the number of hydrogen atom present on the adjacent carbon atom, so there is this one alpha hydrogen present on this carbon atom and there are two alpha hydrogen present on this carbon atom as well.
00:53
Now we know that more the number of alpha hydrogen, more we build the hyperconjugation structures possible for the carbocatine.
01:00
So in this case we can write that there are three alpha hydrogens.
01:06
So in this case there are there is only alpha hydrogen that are providing for the stability of this carbokotype.
01:12
Now if you talk about the second option, we can say that there is only one alpha hydrogen present on the adjacent carbon atom for this carboketime.
01:21
So there is only one alpha hydrogen for the second option.
01:26
And if you talk about the third option, now again the carbocotine is in the same place.
01:31
However, there is this pi bond that is present between these two carbon atoms of the cyclohexene ring.
01:38
So what would happen is that a resonant structure will be formed after the delocalization of this pi bond over this position.
01:47
So the resonant structure formed will be something like this.
02:03
So in this resonant structure, the carbocotine delocalize over this position and the piperatine, bond delocalizes over this position...