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OSCOLPHYS2016 2.3.P.012. The speed of propagation of the action potential (an electrical signal) in a nerve cell depends inversely on the diameter of the axon (nerve fiber). If the nerve cell connecting the spinal cord to your feet is 0.7m long, and the nerve impulse speed is 19 m/s, how long (in s) does it take for the nerve signal to travel this distance? s Additional Materials Reading OSCOLPHYS2016 2.3.P.012. MY NOTES ASK YOUR TEACHER 0.05 X Additional Material Reading

          OSCOLPHYS2016 2.3.P.012.
The speed of propagation of the action potential (an electrical signal) in a nerve cell depends inversely on the diameter of the axon (nerve fiber). If the nerve cell connecting the spinal cord to your feet is 0.7m long, and the nerve impulse speed is 19 m/s, how long (in s) does it take for the nerve signal to travel this distance?
s
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OSCOLPHYS2016 2.3.P.012.
MY NOTES
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oscolphys2016 23p012 the speed of propagation of the action potential an electrical signal in a nerve cell depends inversely on the diameter of the axon nerve fiber if the nerve cell connect 37642

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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OSCOLPHYS2016 2.3.P.012. The speed of propagation of the action potential (an electrical signal) in a nerve cell depends inversely on the diameter of the axon (nerve fiber). If the nerve cell connecting the spinal cord to your feet is 0.7m long, and the nerve impulse speed is 19 m/s, how long (in s) does it take for the nerve signal to travel this distance? s Additional Materials Reading OSCOLPHYS2016 2.3.P.012. MY NOTES ASK YOUR TEACHER 0.05 X Additional Material Reading
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Transcript

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00:01 In this problem, we have been given that the nerve cell which connects the spinal cord to the feet is 1 .2 meters log.
00:10 So if we talk about the length, that's 1 .2 meters and the impulse which is generated by the nerve that moves with a speed of 30 meters per second.
00:22 So we need to compute the time that this nerve signal will take to trouble this length.
00:31 So here we use the expression distance is equal to speed over time...
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