00:01
In this question we have the transfer function.
00:03
So for this circuit we have to find the transfer function by reducing the factors.
00:10
So here we have, so these are connected in series.
00:14
So now here g3 and g4 are in parallel.
00:17
So overall gain will be sum of, so g3, so here these are in parallel.
00:21
Therefore overall gain is the sum.
00:25
Therefore we have the, so by reduction we can erase this and form a series circuit, so which will be g3 plus g4 because they are in parallel.
00:42
So g3 plus g4, so we have it is connected across, so it is connected across g5.
00:50
So this is connected across g5.
00:52
So this is the second arrangement.
00:54
Then we have for the third case, here they shift the h1 and h2 after g5, so gain is divided by g5.
01:05
So here we can shift across g5.
01:08
So here shifting the gain, so we can shift the gain across g5.
01:16
So here we have the gain, gain is shifted.
01:24
So here we have this will be h1 by g5 and this is h2 by g5 because the gain is shifted.
01:32
Now we have g3, g4 and g5 are in series.
01:36
So therefore they can be multiplied.
01:38
So here we can remove, so these are in series, so it can be removed and formed a single circuit.
01:44
Therefore we have, so here we have it is g5 into g3 plus g4 divided by, so g3, so g3 plus g4 into g5 into h3 plus 1.
02:06
Then we have, so that is across h3.
02:11
So here h3 is removed now because we have taken the series connection...