ounces. Suppose that in a particular sample of 50 packages, the mean amount dispensed is 8.172 ounces, with a sample standard deviation of 0.058 ounce. Complete parts (a) and (b). Click here to view page 1 of the critical values for the t Distribution. Click here to view page 2 of the critical values for the t Distribution. a. Is there evidence that the population mean amount is different from 8.17 ounces? (Use a 0.10 level of significance.) State the null and alternative hypotheses. \[ \begin{array}{ll|l|} \mathrm{H}_{0}: \mu & \boldsymbol{\nabla} & \square \\ \mathrm{H}_{1}: \mu & \boldsymbol{\nabla} & \square \end{array} \] (Type integers or decimals.) Identify the critical value(s). The critical value(s) is(are) \( \square \) . (Round to four decimal places as needed. Use a comma to separate answers as needed.) Determine the test statistic. The test statistic is \( \square \) . (Round to four decimal places as needed.) State the conclusion. \( \square \) \( \mathrm{H}_{0} \). There is \( \square \) evidence to conclude the population mean amount is different from 8.17 ounces. b. Determine the p-value and interpret its meaning. The p-value is \( \square \) (Round to four decimal places as needed.) Interpret the meaning of the p-value. Choose the correct answer below. A. The p-value is the probability of not rejecting the null hypothesis when it is false. B. The p-value is the probability of obtaining a sample mean that is equal to or more extreme than 0.002 ounce below 8.17 if the null hypothesis is false. C. The p-value is the probability of obtaining a sample mean that is equal to or more extreme than 0.002 ounce above 8.17 if the null hypothesis is false. D. The p-value is the probability of obtaining a sample mean that is equal to or more extreme than 0.002 ounce away from 8.17 if the null hypothesis is true.
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- Null Hypothesis (\(H_0\)): The population mean amount is equal to 8.17 ounces, i.e., \(\mu = 8.17\). - Alternative Hypothesis (\(H_1\)): The population mean amount is not equal to 8.17 ounces, i.e., \(\mu \neq 8.17\). Show more…
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A manufacturer of chocolate candies uses machines to package candies as they move along a filling line. Although the packages are labeled as 8 ounces, the company wants the packages to contain a mean of 8.17 ounces so that virtually none of the packages contain less than 8 ounces. A sample of 50 packages is selected periodically, and the packaging process is stopped if there is evidence that the mean amount packaged is different from 8.17 ounces. Suppose that in a particular sample of 50 packages, the mean amount dispensed is 8.179 ounces, with a sample standard deviation of 0.044 ounce. Complete parts (a) and (b). a. Is there evidence that the population mean amount is different from 8.17 ounces? (Use a 0.01 level of significance.) State the null and alternative hypotheses. H0: μ = 8.17 H1: μ ≠ 8.17 (Type integers or decimals.) Identify the critical value(s). The critical value(s) is(are) -2.6800, 2.6800 (Round to four decimal places as needed. Use a comma to separate answers as needed.) Determine the test statistic. The test statistic is (Round to four decimal places as needed.)
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A random sample of 49 cans of soda is obtained and the contents are measured. The sample mean is 12.04 oz and the standard deviation is 0.11 oz. Test the claim that the contents of all such cans have a mean different from 12.00 oz, as indicated by the label. Use a 0.05 significance level. State what is the Null and alternative hypotheses? What is the Z score? (round to two decimal places). Find the P value? (round to four decimal places). State the conclusion choose the correct answer:A.The P-value is greater than the significance level. There is sufficient evidence to support the claim that the contents of all such cans have a mean different from 12.00 oz.B.The P-value is less than or equal to the significance level. There is not sufficient evidence to support the claim that the contents of all such cans have a mean different from 12.00 oz.C.The P-value is less than or equal to the significance level. There is sufficient evidence to support the claim that the contents of all such cans have a mean different from 12.00 oz.D.The P-value is greater than the significance level. There is not sufficient evidence to support the claim that the contents of all such cans have a mean different from 12.00 oz.
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