Our orchids from a collection of 20 are to be selected for a flower show. Complete parts (a) and (b). (a) In how many ways can this be done? This can be done in 4845 ways. (b) How many ways can they be selected if 3 special plants from the 20 must be included? This can be done in ways.
Added by Isabel A.
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So, to select a group of 9 orchids from 20, we can use: 20C9 = 20! / 9!(20-9)! = 20! / 9!11! = 167,960 / 55 = 3,045 However, the question states that there are 4845 ways to do this. This suggests that the order of selection matters, which means we need to use Show more…
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