00:01
Hi, i'm david and i'm here to help you answer your question.
00:04
Now let me bring up your question here.
00:07
In this question, will you perform the high body testing about the proportion? here we want to test the proportion p arch node.
00:18
That will be the arch node, sufficient less than, so we'll be less than equal to the 0 .3.
00:30
And then the alternating one.
00:32
That more than 13 % will be be greater than the 0 .3.
00:40
And now in this question we're given the group of the n equal to the 273.
00:48
And we will have x it will only equal to the 63 saturdays mark tuesdays.
00:56
So xing to the 63.
00:59
From here we can find a point estimate be hot, equal to x over n equal to the 63 over 273 then we get equal to 273 equal to 273 equal to the 0 .30 and is there good evidence that more than 30 % of the 10 girls mark to stay thin and after conducting the task where your decision and conclusion are here i believe the alternating one it will be greater than equal and this one will be smaller and therefore the next step we need to compute the test statistics and the test it will equal to the z equal to the p ht minus p over the square root of p times one minus p depending by n.
02:05
So p hath, we file equal to the 0 .2, 308, minus the p equal to 0 .3, dividing by the square root of the 0 .3 times 1 minus 0 .3 over n will be 273.
02:20
If we compute this one, we will have equal to 0 .3 times 0 .7, divided by 273, square root the answer, then we have the 0 .2, 308 minus 0 .3, the value by the answer, equal to the minus 2 .495.
02:45
Then the next time we will compute the b value.
02:50
B value just equal to the probability because here we have the 1 -tell.
02:56
Therefore the probability in the b value equal to the z smaller than minus 2 .495...