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A \( \pi \) bond arises from "sideways" overlap of two parallel p orbitals. The electron density lies above and below a plane containing the 2 nuclei that is perpendicular to the orbitals.
\( \pi \) bond
What atomic or hybrid orbitals make up the \( \pi \) bond between \( \mathbf{N} \) and \( \mathbf{O} \) in nitrosyl bromide, \( \mathrm{NOBr} \) ?
\( \square \) orbital on \( \mathbf{N}+ \) \( \square \) orbital on 0
How many \( \sigma \) bonds does \( \mathbf{N} \) have in \( \mathbf{N O B r} \) ? \( \square \)
How many \( \pi \) bonds does \( \mathbf{N} \) have? \( \square \)
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