P16B.6 (a) Calculate the drift speeds of Li+, Na+, and K+ in...

Name: P16B.6 (a) Calculate the drift speeds of Li+, Na+, and K+ in water when a potential difference of 100 V is applied across a 5.00 cm conductivity cell. Refer to the Resource section for values of ion mobilities. (b) Calculate how long it takes each ion to move from one electrode to the other. (c)
Uploaded: 2022-04-11T20:03:01-08:00
Duration: 9 min 38 s
Channel: Sri K
Description: P16B.6 (a) Calculate the drift speeds of Li+, Na+, and K+ in water when a potential difference of 100 V is applied across a 5.00 cm conductivity cell. Refer to the Resource section for values of ion mobilities. (b) Calculate how long it takes each ion to move from one electrode to the other. (c)

P16B.6 (a) Calculate the drift speeds of Li+, Na+, and K+ in water when a potential difference of 100 V is applied across a 5.00 cm conductivity cell. Refer to the Resource section for values of ion mobilities. (b) Calculate how long it takes each ion to move from one electrode to the other. (c)

Transcript

00:01 Hello students here we have multiple questions.

00:04 Let us consider the first question we are going to find out drift disputes of lithium, sodium and potassium.

00:12 The key note here is calculate the drift speeds of the avomation ions.

00:18 Let us consider the answer here.

00:22 The potential difference of 100 volts that is applied across 5 centimeters conductivity cell.

00:36 Potential applied here v is equal to 100 volts.

00:41 Length of the cell 5 centimeters.

00:47 Now let us consider the explanation further taking the formula.

00:57 So the electric field in the cell is equal to potential across the cell divided by length of the cell.

01:05 Now let us see the potential that is given in the question that is 100 volts divided by 5 centimeters that is 20 volts per centimeter so electric field in the cell is equal to 20 volts per 10 to the power of so that is 20 volt per 10 square meter that is 20 into 10 square volt per meter now we know that drift speed vd is equal to mu multiplied by xxelon for ionic mobility that is new is equals to we have the values let us mention the values here for sodium it is 5 .19 multiplied by 10 to the power of minus 4 square centimeter per second volt whereas for lithium 4 .01 multiplied by 10 to power of minus 4 cm square per second per bolt.

02:42 Ionic mobility new is equal to 7 .62 multiplied by 10 the power of minus 4 square centimeter per second per bolt.

02:55 Now let us calculate drift velocity the velocity of charged particles to move across an applied electric field is drift to velocity.

03:05 For lithium vd is equal to new multiplied by epsilon that is to 4 .01 multiplied by 10 to power of minus 4 per square centimeter per s old multiplied by 20 bolt per 2 this uses 8 .0 to 10 to the power of minus 3 centimeter cube per s now for sodium let us calculate drift velocity 5 .19 multiplied by 10 to the power of minus 4 square centimeter per second bolt multiplied by 20 volt per centimeter.

04:06 This on purposeification gives us 10 .38 multiplied by 10 to the power of minus 3 centimeter per second.

04:21 Now for potassium, let us consider to be velocity 7 .62 multiplied by 10 to power of minus 4 square centimeter per second volt multiplied by 20 old per centimeter.

04:42 That is equals to 15 .24 multiplied by 10 power of minus 3, centimeter per second...

Question

P16B.6 (a) Calculate the drift speeds of Li+, Na+, and K+ in water when a potential difference of 100 V is applied across a 5.00 cm conductivity cell. Refer to the Resource section for values of ion mobilities. (b) Calculate how long it takes each ion to move from one electrode to the other. (c)

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