P8Q6: If the resistance in an RC circuit increases, does the capacitor charge time increase or decrease? Explain, helped by the formula of the time constant Ď„ (tau). P8Q8: The voltage equation for capacitor discharge in the RC circuit is:
Added by Jeffrey P.
Step 1
The time constant is given by the formula: \[ \tau = R \times C \] where: - \( \tau \) = time constant - R = resistance - C = capacitance ** Show more…
Show all steps
Your feedback will help us improve your experience
Shaiju T and 93 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The charge on a capacitor decrease $\eta$ times in time $t$, when it discharges through a circuit with a time constant $\tau$, a. $t=\eta \tau$ b. $\tau=\operatorname{tnn}$ c. $t=\tau(\ln \eta-1)$ d $t=\operatorname{tln}\left(1-\frac{1}{\eta}\right)$
Does inserting a dielectric into a capacitor increase or decrease the energy stored in the capacitor? Explain your answer.
Obtain an expression for the rate of increase ( $d V / d t$ ) of the voltage across a charging capacitor in an $R C$ circuit. Evaluate your result at time $t=0,$ and show that if the capacitor continued charging steadily at this rate, it would reach full charge in exactly one time constant.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD