Question

Page 6 of 8 Q4: (a) $K'\frac{W}{L} = 4mA/V^2$, $V_T$=1V, ?=0 Calculate the value of resistor so that $I_D$=2mA and ±2V output swing is available at the drain of NMOS. (8+4=12) $V_{DD}$=10V $R_D$=? $R_{G1}$=? $R_{G2}$ > 20 ?? (b): Recalculate the value of $R_{G1}$, if $R_{G2}$ is removed for the same data as part a)

          Page 6 of 8
Q4: (a) $K'\frac{W}{L} = 4mA/V^2$, $V_T$=1V, ?=0 Calculate the value of
resistor so that $I_D$=2mA and ±2V output swing is available at
the drain of NMOS. (8+4=12)
$V_{DD}$=10V
$R_D$=?
$R_{G1}$=?
$R_{G2}$ > 20 ??
(b): Recalculate the value of $R_{G1}$, if $R_{G2}$ is removed for the same data as part a)

Page 6 of 8
Q4: (a) K'(W)/(L) = 4mA/V^2, VT=1V, ?=0 Calculate the value of
resistor so that ID=2mA and ±2V output swing is available at
the drain of NMOS. (8+4=12)
VDD=10V
RD=?
RG1=?
RG2 > 20 ??
(b): Recalculate the value of RG1, if RG2 is removed for the same data as part a)

Added by Dennis D.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Aakash Goyal

Step 1

Given that VpD = 10V and Ip = 2mA, we can use Ohm's Law to calculate the value of Rp. VpD = Ip * Rp 10V = 2mA * Rp Rp = 10V / 2mA Rp = 5kΩ Show more…

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Page 6 of 8 VpD = l0V Q4: (a) K'aW/L = 4mA/V^2, Vtn = 1V, = 0. Calculate the value of resistor so that Ip = 2mA and 2V output swing is available at the drain of NMOS. (8+4=12) Rp = ? RG1 = ? RG2 = 20 M (b): Recalculate the value of Ras, if Rez is removed for the same data as part a)