Pair =1.29k(g)/(m^(3))
Group work
Re=(F_(
ho ))/(F_(eta ))∼(
ho vL)/(eta ),{(:[F_(
ho )∼bv^(2)]),(F_(eta )∼b^(')v):}
A short time after deploying her parachute with a cross
sectional area of 8m^(2), a 60kg skydiver falls toward the ground
with a constant speed of 7(m)/(s) when the acceleration due to
gravity is constant and equal to 9.8(m)/(s^(2)).
A. What is Reynolds number for the diver?
B. Is the drag force primarily inertial or viscous?
C. Draw a free body diagram for the diver when falling at
constant speed
D. What is the value for b for this skydiver with an open
parachute?
g=9.8(m)/(s^(2))
Pair=1.29Kg1m3
2/27/2024
Re Fo Fn
pUL n
Fp~ bu2 Group work Fn~b'U A short time after deploying her parachute with a cross sectional area of 8 m2 , a 60 kg skydiver falls toward the ground with a constant speed of 7 m/s when the acceleration due to gravity is constant and equal to 9.8 m/s2. A.What is Reynolds number for the diver? B. Is the drag force primarily inertial or viscous? C. Draw a free body diagram for the diver when falling at constant speed D. What is the value for b for this skydiver with an open parachute?
Re=FP=PUL
P=1.29Kg1m3 9=9.8m1s2
=8m2