5. (Paired t test) An article in the Journal of Strain Analysis (1983, Vol. 18, No. 2) compares several methods for predicting the shear strength for steel plate girders. Data for two of these methods, the Karlsruhe and Lehigh procedures, when applied to nine specific girders, are shown in Table 10-2. We wish to determine whether there is any difference (on the average) between the two methods. Use ? = 0.05. Table 10-2 Strength Predictions for Nine Steel Plate Girders (Predicted Load/Observed Load) Girder Karlsruhe Method Lehigh Method Difference d_i S1/1 1.186 1.061 0.119 S2/1 1.151 0.992 0.159 S3/1 1.322 1.063 0.259 S4/1 1.339 1.062 0.277 S5/1 1.200 1.065 0.138 S2/1 1.402 1.178 0.224 S2/2 1.365 1.037 0.328 S2/3 1.537 1.086 0.451 S2/4 1.559 1.052 0.507 a. Write the proper hypothesis for the scenario. b. Calculate the test statistic. c. Make the decision using critical value method. d. Make the decision using p value method. e. Make the decision using confidence interval method.
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Alternative hypothesis (Ha): There is a difference between the average shear strength predicted by the Karlsruhe and Lehigh procedures. Show more…
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An article in the Journal of Strain Analysis (1983, Vol. 18, No. 2) compares several methods for predicting the shear strength for steel plate girders. Data for two of these methods, the Karlsruhe and Lehigh procedures, when applied to nine specific girders, are shown in the accompanying Table. Construct a 95% confidence interval on the difference in mean shear strength for the two methods. Round your answer to four decimal places (e.g. 98.7654). Girder Karlsruhe Method Lehigh Method Difference dj S1/1 1.177 1.060 0.117 S2/1 1.147 0.991 0.156 S3/1 1.323 1.070 0.253 S4/1 1.334 1.065 0.269 S5/1 1.202 1.061 0.141 S2/1 1.403 1.176 0.227 S2/2 1.372 1.046 0.326 S2/3 1.530 1.090 0.440 S2/4 1.566 1.049 0.517
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