Part 1. Consider two forces at right angles to each other,...

Part 1. Consider two forces at right angles to each other, one equal to the weight of 300 g and the other to the weight of 500 g (2.94 and 4.90 Newtons, respectively). Let the 4.90 N weight be at 0°, and the 2.94 N weight be at 90°. Set these up on the force table and find by experiment the magnitude and direction of the force on a third string which will be equal and opposite to the effect of the two forces working together. This force is called the equilibrant. Write the magnitude (in Newtons) and direction of the equilibrant in your lab notebook. The equilibrant is equal and opposite to their resultant. Write down the magnitude and directions of the resultant, expressing the magnitude in Newtons. Next compute the resultant of these same two forces by use of the Pythagorean theorem, which applies in the case where the forces are at right angles to each other. Draw a force parallelogram (a rectangle in this case) to scale letting 1 Newton equal a length of 1 cm and, using one triangle, find the angle of the resultant, using: sin ? = 2.94N / R How does this (theoretical) calculated value compare with the resultant determined using the force table? Calculate the per cent difference in magnitude and angle.

Transcript

00:01 So we'll be looking at using a force table to determine, experimentally determine the resultant and equilibrium of a system of forces, as well as to find the angle of the resultant and also apply by the other chance to determine the resultant as well as make comparisons.

00:30 Let's see we have this are force board, a false table.

00:42 And we asked that at zero degree, one string should pass through there.

00:53 So let's call at f1 and gain masses there.

00:59 And it will give us, let me do our motivation with transportation to gravity.

01:05 With masses, we're going to have a force of 4 .9 a new thing there.

01:13 And then if we also consider of 90 degrees table i'll do this against the force so let's call the force there we are told that the force would give us 2 .9 2 .9 for muting okay but i'm blinded in mass by acceleration to gravity so this is 90 degree upon 90 degree right then we need an another string again to drag it so you can call these the first table that's you will have called this on f3 so you can just draw the first you can draw the first diagram now the vector diagram you know give us a new apply scale of cm one centimeters we go to one centimeter we go to one centimeter we go to one meter we go to one so on our ruler, this is 90 degree.

03:31 On our ruler, we'll pick 4 .9 centimeters, okay? we use as set squares that i want to have to do for, like, if we have the one for the 590, we have the 60, 90, 30.

03:53 We align them to each of the line, the strings.

03:56 Strings and for this one f1 who drag it out there are 4 .9 that is those are f to measure it and draw it line of 4 .9 centipter resulting 4 .9 yeartie so this is f1 is equal to 4 .9 mutin so do the same to align instrument again together, we apply them together and draw to this other direction.

04:53 It gives us this, okay? we draw a line that is 2 .94 centimeter, right? so we call these, it's coming like this.

05:29 Okay, so we call this f2.

05:34 We know that it is a 2 .94 newton.

05:40 So we can apply our what you call it now these are the triangle law the result on normally should join from in the reverse direction because the triangle in the reverse direction so you have something that look like this but the result and we know is going this way for sport so this is our sorry the equilibrium that's that equilibrium and this are result that came yeah so we call this angle theta all right so this is our resultant coming this way now you measure here with your ruler again and do use your one sent it up to one neutral do your convection and i had arrow equal to 5 .7 newtine all right i measure this angle and it gave me 31 this angle theta 31 .31 .5 degrees degrees right so remember that we're two to draw this diagram the rectal the this fault diagram we're right the parallelogram but what we actually have here that is a rectangle so you just need to do is to just to complete this one draw on a parallel line to this one to f1 on this other side you can just use broken line to complete it something that look like this and draw another parallel line okay using the measurements all right i've been done that you can so this our resultant resultant this one and this is our equilibrium acting in the opposite direction to the resultant okay so this is equilibrium all right then having this one so we can go ahead now and then these are pythagoras to confirm our answer.

08:36 We use patagoras at the result and is going to give us equal to the root of f1 squared plus f2 is equal to the root of f1 is what? f1 is 4 .9.

09:08 The f2 is 2 .94.

09:12 Square it to 0 .94 square...

Question

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