00:01
Hello everyone, let us look into the question.
00:03
Here we are considering the question of tossing two dice at a time.
00:07
So total number of outcomes equal to 36 and the probability of winning which is 2, 5, 5, 2, 4, 3, 3, 4, 1, 6 and 6, 1 that is getting the total as 7 and getting the total as 11 is the combination is 5, 6 and 6, 5.
00:33
So here we will get the total as 11 and here we will get 7.
00:37
So from this we can say that 8 outcomes are the possible outcomes.
00:43
Hence that is getting 7 or 11 is the target.
00:48
So possible outcomes equal to 8.
00:52
What is the probability that a player wins the game on the first roll of dice? so among 36 outcomes there are 6 ways to get a 7 and 2 ways to get an all.
01:13
Then probability of win on first roll equal to 6 plus 2 divided by 36 which is 8 by 36 so which is 2 by 9.
01:27
Third one, so probability of losing...