Part:-1 Q1. A rod \( 200 \mathrm{~cm} \) long and of diameter \( 3.0 \mathrm{~cm} \) is subjected to an arial pull of \( 30 \mathrm{kN} \). If the young's modulus of the material of the rod is \( 2 \times 10^{5} \mathrm{~N} / \mathrm{mm}^{2} \), determine. (i) Sthess (2) Strain (3) elongation of rod
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A structural steel rod has a radius of $10 \mathrm{~mm}$ and a length of $1 \mathrm{~m}$. A $100 \mathrm{kN}$ force $F$ stretches it along its length. The strain in rod is $1.59 \times 10^{-n}$ then the value of $\mathrm{n}$ is. Given that the Young's modulus $E$ of the structural steel is $2.0 \times 10^{11} \mathrm{~N} / \mathrm{m}^{-2}$.
A cylindrical rod of steel $\left(E=207 \mathrm{GPa}, 30 \times 10^{\circ}\right.$ psi) having a yield strength of $310 \mathrm{MPa}(45,000$ psi) is to be subjected to a load of $11,100 \mathrm{~N}$ (2500 $\left.\mathrm{Ib}_{i}\right)$. If the length of the rod is $500 \mathrm{~mm}(20.0 \mathrm{in}$.), what must be the diameter to allow an elongation of $0.38 \mathrm{~mm}(0.015$ in.)?
A cylindrical rod of steel $(E=207 \mathrm{GPa}, 30 \times$ $\left.10^{6} \text { psi }\right)$ having a yield strength of $310 \mathrm{MPa}$ $(45,000 \mathrm{psi})$ is to be subjected to a load of $11,100 \mathrm{N}\left(2500 \mathrm{lb}_{\mathrm{f}}\right) .$ If the length of the rod is $500 \mathrm{mm}(20.0 \text { in. }),$ what must be the diameter to allow an elongation of $0.38 \mathrm{mm}(0.015 \text { in. }) ?$
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