Part 1A) Use the binomial formula to calculate the following probabilities for an experiment in which n=6 and p=0.75
a. the probability that x is at most 1
b. the probability that x is at least 5
c. the probability that x is less than 1
Part 1B) If a binomial distribution applies with a sample size of n=20, find the values below.
a.
The probability of 5 successes if the probability of a success is 0.20
b.
The probability of at least 7 successes if the probability of a success is 0.35
c.
The expected value, n=20, p=0.10
d.
The standard deviation, nequals=20, p=0.10
Part 1C) Suppose that 40% of all home buyers will do some remodeling to their home within the first five years of home ownership. Assuming this is true, use the binomial distribution to determine the probability that in a random sample of 20homeowners, 5 or fewer will remodel their homes. Use the binomial table. The probability that 5 or fewer people in the sample indicate that they will remodel their homes is enter your response here.
(Round to four decimal places as needed.)
Cumulative Binomial Distribution Table
x
Cumulative Binomial Distribution Table
n=15
x 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
p = 0.10 0.2059 0.5490 0.8159 0.9444 0.9873 0.9978 0.9997 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000
p = 0.15 0.0874 0.3186 0.6042 0.8227 0.9383 0.9832 0.9964 0.9994 0.9999 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000
p = 0.20 0.0352 0.1671 0.3980 0.6482 0.8358 0.9389 0.9819 0.9958 0.9992 0.9999 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000
p = 0.25 0.0134 0.0802 0.2361 0.4613 0.6865 0.8516 0.9434 0.9827 0.9958 0.9992 0.9999 1.0000 1.0000 1.0000 1.0000 1.0000
p = 0.30 0.0047 0.0353 0.1268 0.2969 0.5155 0.7216 0.8689 0.9500 0.9848 0.9963 0.9993 0.9999 1.0000 1.0000 1.0000 1.0000
p = 0.0 0.0 0.0 0.1 0.3 0.5 0.7 0.8 0.9 0.9 0.9 0.9 0.9 1.0 1.0 1.0
n =20
x 0 1 2 3
p = 0.10 0.1216 0.3917 0.6769 0.8670
p = 0.15 0.0388 0.1756 0.4049 0.6477
p = 0.20 0.0115 0.0692 0.2061 0.4114
p 0.25 0.0032 0.0243 0.0913 0.2252
p 0.30 0.0008 0.0076 0.0355 0.1071
p = 0.0 0.0 0.0 bo
Print
Done