Question

Part 2 Find the solution showing all work. 13- A solid non-conducting sphere of radius 2 cm has a charge of 8 µC. a. Find the electric field and electric potential at: i. r = 1 cm from the center of the sphere? (6 pts) $ \frac{q}{4 \pi \epsilon_0 r^2} = \frac{1 \times 10^{-6} (9 \times 10^9)}{0.01^2} = 9 \times 10^7 (N/C) \times $ $ \frac{q}{4 \pi \epsilon_0 r} = \frac{1 \times 10^{-6} (9 \times 10^9)}{0.01} = 9 \times 10^5 V \times $

          Part 2 Find the solution showing all work.
13- A solid non-conducting sphere of radius 2 cm has a charge of 8 µC.
a. Find the electric field and electric potential at:
i. r = 1 cm from the center of the sphere? (6 pts)
$ \frac{q}{4 \pi \epsilon_0 r^2} = \frac{1 \times 10^{-6} (9 \times 10^9)}{0.01^2} = 9 \times 10^7 (N/C) \times $
$ \frac{q}{4 \pi \epsilon_0 r} = \frac{1 \times 10^{-6} (9 \times 10^9)}{0.01} = 9 \times 10^5 V \times $

Part 2 Find the solution showing all work.
13- A solid non-conducting sphere of radius 2 cm has a charge of 8 µC.
a. Find the electric field and electric potential at:
i. r = 1 cm from the center of the sphere? (6 pts)
(q)/(4 πϵ0 r^2) = (1 × 10^-6 (9 × 10^9))/(0.01^2) = 9 × 10^7 (N/C) ×
(q)/(4 πϵ0 r) = (1 × 10^-6 (9 × 10^9))/(0.01) = 9 × 10^5 V ×

Added by Bonnie T.

University Physics with Modern Physics

Wolfgang Bauer, Gary D. Westfall 1st Edition

Chapter 23

Instant Answer

Solved by Expert Adi S

Step 1

The electric field at a point outside a uniformly charged sphere can be found using the formula: E = k * (Q / r^2) where E is the electric field, k is the electrostatic constant (9 x 10^9 Nm^2/C^2), Q is the charge of the sphere, and r is the distance from the Show more…

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A solid non-conducting sphere of radius 2 cm has a charge of 8 C. Find the electric field and electric potential at r=1 cm from the center of the sphere.