Question

Part 3: Tension & ratios 1. Determine the tension in the string for Part 1 & Part 2 (I recommend making a force diagram first). $F_{T1}$= (No Response) $F_{T2}$= (No Response) 2. Using the formula $v = \sqrt{\frac{F_T}{m/L}}$ and the tension values you just calculated, determine the ratio $\frac{V_1}{V_2}$. Assume the linear mass density ($m/L$) is the same for both cases. $\frac{V_1}{V_2}$ = (No Response) 3. Using your values for average wave speed from Part 1 & Part 2, determine the ratio $\frac{V_1}{V_2}$. Ideally, this ratio will be the same as the theoretical value you just calculated. $\frac{V_1}{V_2}$ = (No Response)

          Part 3: Tension & ratios
1. Determine the tension in the string for Part 1 & Part 2 (I recommend making a force diagram first).
$F_{T1}$= (No Response)
$F_{T2}$= (No Response)
2. Using the formula $v = \sqrt{\frac{F_T}{m/L}}$ and the tension values you just calculated, determine the ratio $\frac{V_1}{V_2}$. Assume the linear mass density ($m/L$) is the same for both cases.
$\frac{V_1}{V_2}$ = (No Response)
3. Using your values for average wave speed from Part 1 & Part 2, determine the ratio $\frac{V_1}{V_2}$. Ideally, this ratio will be the same as the theoretical value you just calculated.
$\frac{V_1}{V_2}$ = (No Response)

Part 3: Tension ratios
1. Determine the tension in the string for Part 1 Part 2 (I recommend making a force diagram first).
FT1= (No Response)
FT2= (No Response)
2. Using the formula v = √((FT)/(m/L)) and the tension values you just calculated, determine the ratio (V1)/(V2). Assume the linear mass density (m/L) is the same for both cases.
(V1)/(V2) = (No Response)
3. Using your values for average wave speed from Part 1 Part 2, determine the ratio (V1)/(V2). Ideally, this ratio will be the same as the theoretical value you just calculated.
(V1)/(V2) = (No Response)

Added by Pamela B.

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