00:01
So here in this question basically we are given this diagram.
00:05
For that diagram in the first part of the question we have to draw its free body diagram.
00:10
Let's say this is a point b here and a vertical force is acting which is 600 lb which is making an angle of 30 degree with the vertical.
00:25
So the distance from this force to that point is 9 feet and the remaining distance from here is 5 feet.
00:34
The reaction rb is acting here in this direction and it is attached to the surface which is slanted at an angle of 30 degree.
00:44
So if we resolve this into two components then this side will give us the t sin of 30 degree and this from here is t cos of 30 degree.
00:56
Now in the first part of the question we have to draw its free body diagram that is fbd.
01:03
So its fbd from here is somewhat like this.
01:09
A normal reaction of 600 cos of 30 degrees acting in this direction and 600 sin of 30 degrees here.
01:19
The reacting force rb is acting perpendicular to the surface from the downward direction.
01:25
Here this is t cos of 30 degree and in this direction the force that is t sin of 30 degrees acting.
01:33
So basically this is the free body diagram of the given diagram...