Question

Part A A 1.7\times 10^{-3} V/m electric field creates a 3.0\times 10^{17} elec/s\ncurrent in a 1.0-mm-diameter aluminum wire.\nWhat is the drift speed?\nExpress your answer with the appropriate units.\n$v_d = $ 6.37 $\frac{\mu m}{s}$\nSubmit Previous Answers Request Answer\nIncorrect; Try Again\nPart B\nWhat is the mean time between collisions for electrons in this wire?\nExpress your answer with the appropriate units.\n$\tau = $ Value Units\nSubmit Request Answer

          Part A
A 1.7\times 10^{-3} V/m electric field creates a 3.0\times 10^{17} elec/s\ncurrent in a 1.0-mm-diameter aluminum wire.\nWhat is the drift speed?\nExpress your answer with the appropriate units.\n$v_d = $ 6.37 $\frac{\mu m}{s}$\nSubmit Previous Answers Request Answer\nIncorrect; Try Again\nPart B\nWhat is the mean time between collisions for electrons in this wire?\nExpress your answer with the appropriate units.\n$\tau = $ Value Units\nSubmit Request Answer

Part A
A 1.7×10^-3 V/m electric field creates a 3.0×10^17 elec/sin a 1.0-mm-diameter aluminum wire.is the drift speed?your answer with the appropriate units.vd = 6.37 (μ m)/(s)Previous Answers Request Answer; Try AgainBis the mean time between collisions for electrons in this wire?your answer with the appropriate units.τ = Value UnitsRequest Answer

Added by Juan Antonio S.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Timothy James

03/12/2023

Step 1

Step 1: Calculate the drift speed using the formula vd = I / (n * A * e), where I is the current, n is the number density of charge carriers, A is the cross-sectional area of the wire, and e is the elementary charge. Show more…

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Part A A 1.710-3 V/m electric field creates a 3.01017 elec/s current in a 1.0-mm-diameter aluminum wire. What is the drift speed? Express your answer with the appropriate units. vd= 6.37 um/s Part B What is the mean time between collisions for electrons in this wire? Express your answer with the appropriate units.