00:01
Let's discuss this question.
00:02
So here we need to calculate the net force that time -wide exerts on 89.
00:07
To keep the calculation fairly simple yet reasonable, we need to consider only the forces due to the o h and the n -h -n combination, assuming that these two combinations are parallel to each other.
00:22
So let's start here we can say a, that is, first of all, let us, let us, calculate the force exerted by o on h and n.
00:57
So here f and o is equal to k multiplied by q1 multiplied by q2 divided by r square.
01:06
So here therefore fn is equal to 8 .99 multiplied by 10 raise to 9 multiplied by minus 1 .6 multiplied by 10 raise to minus 19 multiplied by minus 1 .6 multiplied by 10 raised to minus 19 divided by 0 .28 multiplied by 10 to minus 9 whole square.
01:42
So here we can say this is equal to f n o that is equal to 293 .55 multiplied by 10 raised to minus 11 newton.
02:02
Now we can solve for oh h so here we can say there is a force of attraction between o negative and n negative so here we can say f h is equal to k multiplied by q1 multiplied by q2 divided by r squared so here we can put down the values so f ho is equal to 8 .99 multiplied by 10 raise to 9 multiplied by minus 1 .6 multiplied by 10 raise to minus 19 multiplied by 1 .6 multiplied by 10 raise to minus 19 divided by 0 .1 10 raise 2 minus 9 whole square.
03:10
So here we can say therefore f -h -o is equal to minus 796 .3 4 multiplied by 10 to minus 11 newton...