00:01
So we have given here different parts.
00:02
We have given the hydrocarbon compounds here and we have to name them according to ipsc naming rules.
00:12
The first one is we have this condensed structure here.
00:17
So this is ch3 whole twice.
00:28
Ch c2h5.
00:34
Ch2 ch2 ch3.
00:40
So now this can also be drawn like ch and to this carbon we have two methyl groups attached and we have ch to this carbon we have this ethyl group attached now to complete the valency what we can do so carbon is tetravalent in nature right so now this means we need a single single bond here to complete the valency then we have ch2 ch2 ch3 now selecting the longest carbon chain possible according to the iepac rules so when we are doing this we should make sure that the carbon atoms containing substituents should be given the least position possible so starting from here 1 2 3 4 5 6 so we have 6 carbon atoms in straight carbon chain on second position we have methyl group on third position we have ethyl group so you have two different substituents attest ethyl and methyl whenever this happens so we have to consider the alphabetic order alphabetically e comes first so this this is why we can say three ethyl two methyl and now we have six carbon atom hags is the prefix in is the suffix so this is hexane so three to methyl hexane.
02:25
Okay, now moving on to next.
02:30
So we have v part.
02:35
This time we have ch2 double bond c, c2h5, ch2, ch2, ch3.
02:52
Okay? so now drawing this structure completely, we can say that ch2 double bond c to this carbon atom we have ethyl group attached, then we have ch2, let me write it again, ch2, ch3.
03:25
So now starting from here 1, 2, 3, 4, 5.
03:33
So the double bond is the functional group here and the carbon containing the carbon containing, the functional group should be given the least position possible while counting.
03:46
So now we can name it as two ethyl.
03:55
And then we have five carbon atom chain.
03:58
On first position we have double bond.
04:00
So this is one pentine.
04:06
Okay.
04:08
Two ethyl, one pentine.
04:09
Moving on to next.
04:12
So this time c part, we have ch3 whole twice c double bond c h c2 h5 let me write it again c2h5 and double bond ch2 okay so now this can be drawn as carbon which is attached to two methyl groups double bond ch then carbon attach to ethyl group then double bond ch2 okay so now numbering the carbon chain double bond is here and we have two double bonds actually okay so now when i start the counting from here i have ethyl group when i start the counting from here i have methyl group okay so i am considering here alphabetic order so that's why one two three four five okay so now the name will be so here we have two ethyl four methyl right two ethyl four methyl and then we have two double bonds when the same functional group is being repeated for 2 times, die prefix is used.
06:12
Okay, so this will be 1, 3, panned for 5 carbon atoms, die, in suffix for double bond, die prefix for 2 times double bond repeatants.
06:34
Moving on to next, we have d part.
06:40
This time we have ch3, c, triple bond c c, c2h5 whole twice.
06:55
Okay, so now what we can do.
07:05
So let me completely draw this structure.
07:10
We have this ch3, c triple bond, c, c, c, h, and now this c, ch, and now this ch consists of two ethyl groups, okay, c2h5.
07:22
Or you can see...