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Part A Constant Acceleration Kinematics: A car is traveling at 26.0 m/s when the driver suddenly applies the brakes, causing the car to slow down with constant acceleration. The car comes to a stop in a distance of 120 m. How fast was the car moving when it was 60.0 m past the point where the brakes were applied? 

          Part A
Constant Acceleration Kinematics: A car is traveling at 26.0 m/s when the driver suddenly applies the brakes, causing the car to slow down with constant acceleration. The car comes to a stop in a distance of 120 m. How fast was the car moving when it was 60.0 m past the point where the brakes were applied?
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Part A Constant Acceleration Kinematics: A car is traveling at 26.0 m/s when the driver suddenly applies the brakes, causing the car to slow down with constant acceleration. The car comes to a stop in a distance of 120 m. How fast was the car moving when it was 60.0 m past the point where the brakes were applied?

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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Part A Constant Acceleration Kinematics: A car is traveling at 26.0 m/s when the driver suddenly applies the brakes, causing the car to slow down with constant acceleration. The car comes to a stop in a distance of 120 m. How fast was the car moving when it was 60.0 m past the point where the brakes were applied?
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A car is traveling at 26.0 m/s when the driver suddenly applies the brakes, causing the car to slow down with constant acceleration. The car comes to a stop in a distance of 120 m. How fast was the car moving when it was 60.0 m past the point where the brakes were applied?

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Transcript

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00:01 We have a car traveling at a speed initially of 26 meters per second.
00:06 When the driver slams on the brakes and causes the car to come to a stop in a distance, final velocity of zero, comes to a stop in a distance of 120 meters.
00:18 And we want to know how fast they're moving when they're at a 60 meter point.
00:21 First, we need to find acceleration.
00:24 And so final velocity squared is equal to initial velocity square plus two times acceleration times distance.
00:30 Let's rearrange this to solve for acceleration.
00:35 So divide both sides by two a distance.
00:39 And we get acceleration as equal to final velocity squared, minus initial velocity squared divided by two times distance...
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