00:02
Hi, the first subpart of this question we need to find out the average radiation pressure on a totally absorbing section which can be given by p rar is equal to i by c.
00:38
From the question we have i as 2 ,500 watts per meter square and c is speed of light.
00:48
And has a value of 3 into 10 to the power 8 meter per.
00:55
So upon substituting the values, we can write 2 ,500 divided by 3 into 10 to the power 8, which will give a value of 8 .33 into 10 to the power 6 pascal as the average radiation pressure on a totally absorbing section.
01:21
Now we need to find out this value in the 3.
01:26
Atm also.
01:28
So we can write p rat as equal to 8 .33 into 10 to the power minus 6 pascal into 1 atm corresponds to 1 .013 into 10 to 5 pascal.
01:49
So the value of average radiation pressure atm is 8 .23 into 10 to the power minus 11.
02:00
So that is the required answer for the first subpart of this question.
02:09
How? in this part, we need to find out the average radiation pressure on a totally reflecting surface which can be given by t -rair is equal to 2i by c.
02:42
You already know the values for inc, that will be 2 into 2 ,500 watts per meter square divided by 3 into 10 to the power 8 meter per second which will give a value of average radiation pressure in as 16 .66 into 10 to the power minus 6 pascal...