00:01
Hello students, in this question we are given that a proton has a kinetic energy of 250 mega electron volts and we have to calculate its peak.
00:09
So, first of all, we know that kinetic energy for microscopic particles is equal to mrc square minus m .r c square, where mr denotes the relativistic mass, which is equal to resmarch divided by 1 minus v divided by c whole square and taken the root of this denominator term.
00:32
And there m node denotes the rest mass for the microscopic particle.
00:38
And as we know that in this formula, we can substitute for kinetic energy, we can substitute the value of relativistic mass in terms of rest mass of the object and that would be equal to m0 c square taken common, which is 1 divided by and root taken of 1 minus v.
01:02
V by c whole squared minus 1.
01:06
So this would be the kinetic energy formula for a microscopic particle in terms of its rest mass.
01:15
And as we know that rest mass energy for the proton, which is calculated earlier, that is rest mass energy, rest mass energy for proton, is equal to m0c square, is equal to.
01:33
To 938 .3 mega electron volts.
01:38
And in this equation, we are given this m not c square term.
01:43
We are also given this kinetic energy value and we have to calculate the value of this term v...