Question

PART A: For 300.0 mL of pure water, calculate the initial pH and the final pH after adding 0.032 mol of NaOH. PART B: For 300.0 mL of a buffer solution that is 0.245 M in HCHO2 and 0.310 M in KCHO2, calculate the initial pH and the final pH after adding 0.032 mol of NaOH. (Ka(HCHO2) = 1.8×10^−4.) PART C: For 300.0 mL of a buffer solution that is 0.325 M in CH3CH2NH2 and 0.235 M in CH3CH2NH3Cl, calculate the initial pH and the final pH after adding 0.032 mol of NaOH. (Kb(CH3CH2NH2) = 5.6×10^−4.) The order of answers will be: 'pHinitial, pHfinal

          PART A: For 300.0 mL of pure water, calculate the initial pH and the final pH after adding 0.032 mol of NaOH.
PART B: For 300.0 mL of a buffer solution that is 0.245 M in HCHO2 and 0.310 M in KCHO2, calculate the initial pH and the final pH after adding 0.032 mol of NaOH. (Ka(HCHO2) = 1.8×10^−4.)
PART C: For 300.0 mL of a buffer solution that is 0.325 M in CH3CH2NH2 and 0.235 M in CH3CH2NH3Cl, calculate the initial pH and the final pH after adding 0.032 mol of NaOH. (Kb(CH3CH2NH2) = 5.6×10^−4.)
The order of answers will be: 'pHinitial, pHfinal

Added by Steven G.

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