00:01
So let's say this is charge 1, this is charge 2, and this is our point p where we have to find the electric field.
00:09
So let's first of all let's calculate the electric field due to charge 1 at point b.
00:14
So e1 would be in direction i.
00:18
I mean say this is i direction i cap, this is j cap.
00:22
So e1 would be k means 9 into 10 to 2 .5 .9 times charge is here.
00:30
One nanoculum means 1 times 10 to 3 minus 9.
00:33
Divided by distance square distance is 5 cm so that that means 0 .05 meter square okay this is an icon so even is it is equal to 9 divided by 0 .05 square so if i do the math what we will get we will get 9 divided by 0 .05 means it is equal to 3600 i can okay now let's calculate electric field due to charge 2 means discharge this charge okay we have to find the electric field due to discharge at point p now for for this chart the distance from distance of point p is first of all let's calculate the distance so this is the distance right this blue line is the distance between charge let's say this is d so d is equal to as per pythagos theorem is equal to 5 square plus 10 square means square out of 125 right so now square root of 125 is what 11 11 .18 centimeter okay now let's find the electric field strength first of all let's find electric field strength as you know that as you can see from here that the electric field due to discharge at point p would be in this direction and and due to charge one is in this direction okay so let's calculate e2 first of all e2's magnitude okay and say this is angle theta okay so electric field due to charge 2 magnitude would be k times charge divided by distance square k is 9 to 10 to 10 to the power 9 times 1 into 10 to the power minus 9 column as we've already discussed divide by d square means 125 times 10 to the power minus we got we have got we have got 11 centime 11 .08 centimeter right 11 .18 centimeter means 11 .18 times 10 to the 1 minus 2 meters so we have to square it okay so now the electric field strength would be equal to 9 divided by 125 times 10 to the by minus 4 okay now if i do the math what we will get 9 divided by 125 times 10 to the bar minus 4 is a to approximately 720 newton for pull number okay now the angle theta this angle theta this is the angle theta right as we have already discussed this angle theta we know that that tan theta is equal to perpendicular distance which is 10 divided by uh uh base distance which is 5 here which is given in the question 5 so from here we can say that 10 theta is equal to approximately how much two right so for if at which value so now theta would be what tan inverse of two right so let's let's find the value let's find the angle so tan inverse of two is equal to what sixty three point four three degrees that means this is e2 this is e1 and and the angle between them is 63 .43.
04:24
Now we know that resultant are for two vectors is vector one sorry sorry for this.
04:32
Yeah so formula for resultant of two vectors is nothing but square root of e1 square plus e2 square plus two e1 e2 cost of angle between that okay...